2003 in Base6. Page1

2003 in Base Six

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1-25

26-50

51-75

76-100

101-125

126-150

151-175

0 _ten =	(1 + 3 - 1 - 3) / 5	Graeme Taylor (S5)
1 _ten =	1 - 3 +1 - 3 + 5	Iain Brodie (S5)
2 _ten =	1 x (3 + 1) + 3 - 5	Natalie Jackson (S5)
3 _ten =	1 + 3 + 1 + 3 - 5	Laura Matthew (S5)
4 _ten=	1 x 3 x 1 x 3 - 5	Ivailo Zhelev (S5)
5 _ten =	1 + 3 - (1 + 3) + 5	Alex Room (S5)
6 _ten =	(1 + 3 -1) /3 + 5	Kathryn McNeill (S5)
7 _ten =	1 + 3 + 1 - 3 + 5	Neil Porter (S5)
8 _ten =	(-1 + 3 - 1) x 3 + 5	Marcelina Alzamora (S5)
9 _ten =	-1 + 3 - 1 + 3 + 5	Jennifer Banks (S5)
10 _ten =	(1³ +1³) x 5	Adam Duncan (S5)
11 _ten =	1 x 3 x 1 + 3 + 5	Kathryn McNeil (S5)
12 _ten =	-1 + 3 - 1 + 3! + 5	Jennifer Banks (S5)
13 _ten =	1 + 3 + 1 + 3 + 5	Adam Duncan (S5)
14 _ten =	1 x 3 x 1 x 3 + 5	Lyle Moncur (S5)
15 _ten =	1 + 3 x 1 x 3 + 5	Marcelina Alzamora (S5)
16 _ten =	1 + 3! + 1 + 3 + 5	Neil Porter (S5)
17 _ten =	(1 + 3) x 1 x 3 + 5	Robert Goudie (S5)
18 _ten =	1 + 3 -1 + 3 x 5	Euan Forbes (S5)
19 _ten =	1 + 3! + 1 +3! + 5	Neil Porter (S5)
20 _ten=	(1 + 3 +1) x 3 + 5	Robert Goudie (S5)
21 _ten =	(1 + 3)(1 + 3) + 5	Marcelina Alzamora (S5)
22 _ten =	(-1 + 3 x 1)(3! + 5)	Marcelina Alzamora (S5)
23 _ten =	1 x 3! x 1 x 3 + 5	Ivailo Zhelev (S5)
24 _ten =	1 x 3 x 1 x (3 + 5)	Robert Goudie (S5)
25_ten =	(1 + 3 + 1)³ / 5	Sarah Aitken (S5)

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Solutions 26 - 50