1 3410 (3 years calculations required then rounding to the nearest 10)

2 2.36 x 10^-2 % (scientific notation required so not 0.0236)

3 V = ³/₄t + 5 (gradient is ⁴⁵/₆₀ = ³/₄)

4 y = a + b (angle sum is 180, third angle is 180 - y)

5 x = 1.2 or -4.2 (from using the quadratic formula)

6 A bar-graph (include Title, and labelled axes: type of travel and number of replies)

7 (a) l + b = 130 (b) 5l + 8b = 770 (c) l = 90, b = 40 (from simultaneous equations)

8 W = ⁵ / _{p - 4}

9 10.2 cm (SOHCAHTOA in large triangle for AD, reduction of 0.5 for small triangle)

10 d = 37.5 cm (by Pythagoras' Theorem) so it is not rectangular

11 (a) 7 = 4² - 3² (b) 10² - 9² (since 19 is the 10^th odd number)

(c) 2n - 1 (from n² - (n -1)²)

(d) consider (2n-1)(2n+1)=4n²-1 one less than an even number, so odd.

12 y < -1

13 80 kilonewtons (double V when squared gives 4 times V squared so 4 x 20)

14 112 metres (draw in height line BN = h, find AN and NC in terms of h, AN+NC=130 etc)

15 95.0 cm (Cosine Rule)

16 angle BAC = 41.8 or 138.2 (use Area = ¹/₂bcsinA)

17 (a) (x -4)(x + 4) (b) ⁵ / _{2x + 3} (factorise denominator and cancel)

18 Proof (area of square = 72, vol of vase = 1440, vol of cylinder = 720etc)

19 (a) S(90,1) (b) T(30,0.5) and P(150,0.5) (from sinx = ¹/₂)

20 (a) (b) 22

21 (a) 1530 cm² (to 3 sig figs) (²⁸⁰/₃₆₀ x circle area)

(b) 45 cm (cannot round down!)

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